From: Subject: Google Groups: Prikaz niti "JMBG check" Date: Thu, 21 Mar 2002 18:34:54 +0100 MIME-Version: 1.0 Content-Type: multipart/related; boundary="----=_NextPart_000_0000_01C1D107.1881A390"; type="multipart/alternative" X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2600.0000 This is a multi-part message in MIME format. ------=_NextPart_000_0000_01C1D107.1881A390 Content-Type: image/gif Content-Transfer-Encoding: base64 Content-Location: http://groups.google.com/images/threadview_logo.gif R0lGODlhjwA7ANUAAMfIx////xhd17m6uiqSKQQwnWSV4asNAuLj4swgC9ysBtqvn5JbSGVzj4mr 4OvXl4xkCAcneTFZrfT09H4IArHG59ZmUklsSQ1XDJSSkvHEG9qYc4zIi7mOCZt8a8jX7jhPgNPS 0e3LT9dAJokvI/n6+fHYyNra2j55226Gta2srJ2hqAM/wb2Xh+7o4+jw9tri7/P+//rv5tPo0v7+ /v368enr6vv+//D2+Vy8W+/v7/z8/Pb5/Pb29//++/j4+CH5BAAAAAAALAAAAACPADsAAAb/wIBw SCwaj8ikcslsOp/QqHRKrVqv2Kx2y+16v+CweEwum8/oIc3Gts3etLR8bizNAJx8jkAY7OJmOy8w HxWGHzAvP3RkNDN5kHwZOBOLYzswDigCAiydnCgoBg4VLz6MYCU/OAA5exgqJzYTgF8lHwadEikp 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http://groups.google.com/groups?hl=hr&ie=ISO-8859-2&oe=ISO-8859-2&threadm=MPG.15581c8352afdfb0989ba5%40news.hinet.hr&rnum=15&prev=/groups%3Fq%3DJMBG%2Bgroup:hr.comp.*%26start%3D10%26hl%3Dhr%26ie%3DISO-8859-2%26oe%3DISO-8859-2%26selm%3DMPG.15581c8352afdfb0989ba5%2540news.hinet.hr%26rnum%3D15 Google Groups: Prikaz niti "JMBG check" ------=_NextPart_001_000B_01C1D107.1887BE10 Content-Type: application/octet-stream Content-Transfer-Encoding: quoted-printable Content-Location: http://groups.google.com/groups?hl=hr&ie=ISO-8859-2&oe=ISO-8859-2&frame=left&th=ad1908cefb68799e&prev=/groups%3Fq%3DJMBG%2Bgroup:hr.comp.*%26start%3D10%26hl%3Dhr%26ie%3DISO-8859-2%26oe%3DISO-8859-2%26selm%3DMPG.15581c8352afdfb0989ba5%2540news.hinet.hr%26rnum%3D15&seekm=MPG.15581c8352afdfb0989ba5%40news.hinet.hr
3D""=20
Tema:
 JMBG check

News-grupa:
 hr.comp.programiranje

3D""=20
3D""=20Natrag 3D""=20Bez okvir=E2 3D""=20Poredaj po datumu
3D""=20

3D""=20[ Night Rider = ] 06 Apr 2001

3D""=20|-mario = mikac 06 Apr 2001
3D""=20| |-[ Night Rider = ] 07 Apr 2001
3D""=20| \-Tomislav = Vujec 23 Apr 2001
3D""=20\-Damir = Seligo 09 Apr 2001
3D""=20  |-Igor = Ostriz 09 Apr 2001
3D""=20  |-mario = mikac 09 Apr 2001
3D""=20  | \-Gjuro Pedala -=20 AhRiMaN 15 Apr 2001 =
  |   \-Gjuro Pedala -=20 AhRiMaN 15 Apr 2001 =
  |-10 Gjuro Pedala -=20 AhRiMaN 15 Apr 2001 =
  | \-11 Igor = Ostriz 17 Apr 2001
3D""=20  |   |-12 Tomislav = Vujec 23 Apr 2001
3D""=20  |   \-13 Gjuro Pedala -=20 AhRiMaN 30 Apr 2001 =
  \-14 Damir = ?eligo 18 Apr 2001
3D""    \-15 Gjuro Pedala -=20 AhRiMaN 30 Apr 2001=20

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3D""=20
Poruke 1-10 iz=20 niti
Sljede=E6a=20 5
Sko=E8i na [ Kraj=20 niti ]

Message 1 in=20 thread
Od:[ Night Rider ] (aquatica@softhome.net)
Tema:= JMBG=20 check
News grupe:hr.comp.programiranje
View this article=20 only
Datum:2001-04-06 12:12:01 = PST=20

Pozdrav,

Netko sigurno ima algoritam za provjeru JMBGa, pa ako moze nek baci
source, moze pascal ili c ...  Hvala unaprijed ...


--=20
 : Night Rider -a-k-a- [NeveR]  http://nrx.da.ru/ ...
 : When you see what you want, it possesses you ...
Message 2 in=20 thread
Od:mario mikac (mario@mminzenjering.com)
T= ema:Re:=20 JMBG check
News grupe:hr.comp.programiranje
View this article=20 only
Datum:2001-04-06 14:40:07 = PST=20
"[ Night Rider ]" wrote =
:
> Netko sigurno ima algoritam za provjeru =
JMBGa, pa ako moze nek baci
> source, moze pascal ili c ...  Hvala unaprijed ...
>

Vec je bilo na grupi, pa ja spremio. Dakle:

Ako oznacimo prvih 12 znamenki sa:
ABCDEFGHIJKL
treba izracunati trinaestu kontrolnu znamenku Z.

Formula je:
x =3D 2f+3e+4d+5c+6b+7a+2l+3k+4j+5i+6h+7g
tj. x=3D 7*(A+G)+6*(B+H)+5*(C+I)+4*(D+J)+3*(E+K)+2*(F+L)

y =3D x%11  ( x  mod 11 -> cjelobrojni ostatak dijeljenja s 11 )
IF y =3D 0
    Z =3D 0
ELSEIF y =3D 1
    Z =3D 5
ELSE
    Z =3D 11 - y
ENDIF

I to je to.
Message 3 in=20 thread
Od:[ Night Rider ] (aquatica@softhome.net)
Tema:= Re:=20 JMBG check
News grupe:hr.comp.programiranje
View this article=20 only
Datum:2001-04-07 09:12:02 = PST=20
Razmisljajuci kako bi =
Duke Nukem reagirao na Teletabise vidjeh da=20
 mario mikac kaze :


>Formula je:
>x =3D 2f+3e+4d+5c+6b+7a+2l+3k+4j+5i+6h+7g
>tj. x=3D 7*(A+G)+6*(B+H)+5*(C+I)+4*(D+J)+3*(E+K)+2*(F+L)
>
>y =3D x%11  ( x  mod 11 -> cjelobrojni ostatak dijeljenja s 11 )
>IF y =3D 0
>    Z =3D 0
>ELSEIF y =3D 1
>    Z =3D 5
>ELSE
>    Z =3D 11 - y
>ENDIF

Hvala, radi ...


--=20
 : Night Rider -a-k-a- [NeveR]  http://nrx.da.ru/ ...
 : When you see what you want, it possesses you ...
Message 4 in=20 thread
Od:Tomislav Vujec (tvujec@yahoo.com)
Tema:Re: = JMBG=20 check
News grupe:hr.comp.programiranje
View this article=20 only
Datum:2001-04-23 07:00:09 = PST=20
"mario mikac" =
<mario@mminzenjering.com> writes:

> Formula je:
> x =3D 2f+3e+4d+5c+6b+7a+2l+3k+4j+5i+6h+7g
> tj. x=3D 7*(A+G)+6*(B+H)+5*(C+I)+4*(D+J)+3*(E+K)+2*(F+L)
>=20
> y =3D x%11  ( x  mod 11 -> cjelobrojni ostatak dijeljenja s 11 )
> IF y =3D 0
>     Z =3D 0
> ELSEIF y =3D 1
>     Z =3D 5

Ako se ne varam, kad je y =3D=3D 1, tada se redni broj preskace i
uzima slijedeci.

> ELSE
>     Z =3D 11 - y
> ENDIF
>=20
> I to je to.
Message 5 in=20 thread
Od:Damir Seligo (dseligo@vip.hr)
Tema:Re: = JMBG check=20
News grupe:hr.comp.programiranje
View this article=20 only
Datum:2001-04-09 01:28:49 = PST=20
> Netko sigurno ima algoritam za provjeru JMBGa, pa =
ako moze nek baci
> source, moze pascal ili c ...  Hvala unaprijed ...
Sto je zakodirano u onim znamenka iza godine u JMBGu (i kako)?

Damir
Message 6 in=20 thread
Od:Igor Ostriz (igor.ostriz@zg.hinet.hr)
T= ema:Re:=20 JMBG check
News grupe:hr.comp.programiranje
View this article=20 only
Datum:2001-04-09 03:14:54 = PST=20
"Damir Seligo" =
<dseligo@vip.hr> wrote in message
http://groups.google.com/groups?selm=3D9arp4d.3vs4gml.1%40s=
trazaplastika.hr...
> > Netko sigurno ima algoritam za provjeru =
JMBGa, pa ako moze nek baci
> > source, moze pascal ili c ...  Hvala unaprijed ...
> Sto je zakodirano u onim znamenka iza godine =
u JMBGu (i kako)?
>
> Damir
>
>

pa, ja pretpostavljam:
prve dvije znamenke: sifra opcine (33 je zagreb)
znamenka spola (0-4 muski, 5-9 zemske), kako odlucuju koja je, pitaj =
boga...
dvije znamenke redni broj upisa u tko zna sta
jedna znamenka checksum

valjda.
Message 7 in=20 thread
Od:mario mikac (DELETEmario@mminzenjering.c= om)
Tema:Re:=20 JMBG check
News grupe:hr.comp.programiranje
View this article=20 only
Datum:2001-04-09 07:32:01 = PST=20
"Damir Seligo" =
<dseligo@vip.hr> wrote :
> Sto je zakodirano u onim znamenka iza godine =
u JMBGu (i kako)?
>

Najvjerojatnije:

7 znamenki: datum rodjenja
2 znamenke: broj registra tj. skupna jedinica lokalne samouprave
3 znamenke: oznaka spola i rednog broja prema za rodjene u istom danu i
    prijavljene u isti registar (vidi prethodno), 000-499 muski, 500-999 =
zenski
1 znamenka: kontrolna znamenka, da se izbjegnu tajp-feleri prilikom
    unosa podataka



------------------------------------------
Remove spam block (DELETE) to reply
Message 8 in=20 thread
Od:Gjuro Pedala - AhRiMaN (ahriman@email.hinet.hr)
Tem= a:Re:=20 JMBG check
News grupe:hr.comp.programiranje
View this article=20 only
Datum:2001-04-15 16:54:05 = PST=20
mario mikac scripsit:

> Najvjerojatnije:
>=20
> 7 znamenki: datum rodjenja
> 2 znamenke: broj registra tj. skupna jedinica lokalne samouprave
> 3 znamenke: oznaka spola i rednog broja prema za rodjene u istom =
danu i
>     prijavljene u isti registar (vidi prethodno), 000-499 muski, =
500-999 zenski
> 1 znamenka: kontrolna znamenka, da se izbjegnu tajp-feleri prilikom
>     unosa podataka

nema TOLIKO znamenki.

--=20
[ http://ahri.cjb.net/ ] [ http://maghacker.cjb.net/ ]
"KLIMAKTERIJ - prostor, odnosno mjesto, gdje su=20
tlak i temperatura takvi da ne daju tijelu da=20
se normalno razvija"   - Drug Mihalj, 2000. Kemija.
Message 9 in=20 thread
Od:Gjuro Pedala - AhRiMaN (ahriman@email.hinet.hr)
Tem= a:Re:=20 JMBG check
News grupe:hr.comp.programiranje
View this article=20 only
Datum:2001-04-15 16:54:06 = PST=20
Gjuro Pedala - AhRiMaN =
scripsit:

> nema TOLIKO znamenki.

zanemari, zanemari.... :)

--=20
[ http://ahri.cjb.net/ ] [ http://maghacker.cjb.net/ ]
"KLIMAKTERIJ - prostor, odnosno mjesto, gdje su=20
tlak i temperatura takvi da ne daju tijelu da=20
se normalno razvija"   - Drug Mihalj, 2000. Kemija.
Message 10 in=20 thread
Od:Gjuro Pedala - AhRiMaN (ahriman@email.hinet.hr)
Tem= a:Re:=20 JMBG check
News grupe:hr.comp.programiranje
View this article=20 only
Datum:2001-04-15 17:02:07 = PST=20
Damir Seligo scripsit:

> > Netko sigurno ima algoritam za provjeru =
JMBGa, pa ako moze nek baci
> > source, moze pascal ili c ...  Hvala unaprijed ...
> Sto je zakodirano u onim znamenka iza godine =
u JMBGu (i kako)?

evo, dat cu primjer svog jmbga.
1104984330123.

nazvat cemo 1104984=3DA
33 =3D B
012 =3D C
3 =3D D

A je datum rodjenja
B je opcina u kojoj je rodjen... 33 je zagreb, 59 je split ako se ne=20
varam.
C je redni broj pod kojim je osoba rodjena tog dana u toj zupaniji.
dakle... od 000-499 su decki, a od 500-999 su cure.
ako imas broj 020 znaci da si 21. koji se rodio tada u toj opcini.
D je kontrolni broj.


--=20
[ http://ahri.cjb.net/ ] [ http://maghacker.cjb.net/ ]
"KLIMAKTERIJ - prostor, odnosno mjesto, gdje su=20
tlak i temperatura takvi da ne daju tijelu da=20
se normalno razvija"   - Drug Mihalj, 2000. Kemija.

Sljede=E6a=20 5
Sko=E8i na [ Kraj=20 niti ]


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